4n^2-24n-160=0

Solution for 4n^2-24n-160=0 equation:

4n^2-24n-160=0

a = 4; b = -24; c = -160;
Δ = b2-4ac
Δ = -242-4·4·(-160)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-56}{2*4}=\frac{-32}{8}
=-4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+56}{2*4}=\frac{80}{8}
=10
$